Use VBA to randomize blocks of cells in an Excel workbook in C#


This is another quick excursion into VBA programming. This example uses a VBA macro to let you randomize cells in an Excel workbook. If you select a contiguous block of cells and click the Randomize button, the following macro executes.


Sub Randomize()
Dim rng As Range
Dim num_rows As Integer
Dim num_cols As Integer
Dim temp() As Object
Dim row As Integer
Dim col As Integer
Dim swap_row As Integer
Dim temp_object As String
' Get the selected range.
Set rng = Application.Selection
num_rows = rng.Rows.Count
num_cols = rng.Columns.Count
If ((num_rows < 2) Or (num_cols < 1)) Then
MsgBox "You must select at least 2 rows and 1 column."
Exit Sub
End If
' Randomize.
For row = 1 To num_rows - 1
' Pick the row to swap with this row.
swap_row = row + CInt(Int((num_rows - row + 1) * Rnd()))
' Swap the rows.
If (row <> swap_row) Then
For col = 1 To num_cols
temp_object = rng(row, col)
rng(row, col) = rng(swap_row, col)
rng(swap_row, col) = temp_object
Next col
End If
Next row
End Sub

The code starts by getting the number of rows and columns selected. If you have not selected at least 2 rows and 1 column, the macro complains and exits.

Next the code loops over all of the rows you selected except the last one. For each row, the code picks a random one of the following rows and swaps the cells in the two rows. (When I say “row” here I mean only the cells you selected in the workbook’s row, not the entire row. For example, if you select cells in columns F through H, only those cells are swapped.)

The code doesn’t need to consider the last row you selected because there are no rows after it with which to swap. That row has already been considered for swapping with earlier rows so it may have been swapped already.

   

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